VintageGenious 3d ago • 100%
Yes I thinks this tells much
VintageGenious 3d ago • 100%
I have evidence, but needed more
VintageGenious 3d ago • 100%
Yes I mean he's not defining himself as against free speech but his actions show
VintageGenious 3d ago • 100%
Thanks
VintageGenious 3d ago • 100%
I hope I would do better if I was trolling :)
Anyway thanks for the search keywords
VintageGenious 3d ago • 100%
Moving to antipolar stance requires way more proofs than moving from a neutral stance. Moreover some people may be more informed than me and they could be useful
VintageGenious 3d ago • 100%
You might be true, Though I wanted thought out answers rather than rage bait
My father is convinced Elon is an idealist but I'd like to show him he's been misled
VintageGenious 2w ago • 100%
Yes the random feed filled with ads unrelated post suggestions and limited to three days is the main issue. i use an Instagram mod but they didn't manage yet to replace the main feed with the friend only feed you can get by clicking on the Instagram button
VintageGenious 2w ago • 100%
The google widget search bar is the thing I hate the most on default Android ui, alongside stupid bixby. Like the windows search bar, it doesn't look good, always stays there and isn't actually useful since you can still search with sometimes one click sometimes two. And the results are horribles with filled MSN-like news
VintageGenious 2w ago • 100%
I thought it's applied to both
VintageGenious 3w ago • 100%
They have a github thread for it https://github.com/AntennaPod/AntennaPod/issues/4159
VintageGenious 3w ago • 66%
Problem is that we don't know how long the ads take, we need to look how sponsor block will handle youtube new ads
VintageGenious 3w ago • 100%
I am developing a podcast app and I can't prevent it either
VintageGenious 3w ago • 100%
SpMp is the best
VintageGenious 4w ago • 100%
The use of for makes sense.
k=0; for (i=0; i<n; i++) k=k+f(i);
is the same as
k=\sum_{i=0}^{n-1} f(i)
and
k=1; for (i=0; i<n; i++) k=k*f(i);
is the same as
k=\prod_{i=0}^{n-1} f(i)
In our case, f(i)=1+r
and
k=1; for (i=0; i<n; i++) k*(1+r);
is the same as
k=\prod_{i=0}^{n-1} (1+r) = (1+r)^n
All of that just to say that exponentiation is an iteration of multiplication, the same way that multiplication is an iteration of addition
VintageGenious 4w ago • 100%
K•(1+r)^n
VintageGenious 2mo ago • 100%
Works well combined with revanced
VintageGenious 2mo ago • 100%
So it's open-source and has even more than Gboard 😁
VintageGenious 2mo ago • 85%
300€ is not disposable for me... People are used to buy phones over 800€ but 300€ is already quite a price
VintageGenious 2mo ago • 100%
Yes I knew about ActivityPub and was told everything works together but realized I hardly see anything from other Fediverse networks, and that interoperability is not implemented everywhere. So that's why I am asking as I don't see anything mastodon in my lemmy client (except for these comments)
I'd like to use both, with preferably the same account, but mainly the same android app
I study math at uni and I was shocked realizing all my teachers use ubuntu on both their laptop and work desktop
Are there pirated contents that you very like and eventually give money to the creator, and where do you find the creators?